Match the following:1. Succinic acidp. 12 ATP | vedclass

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(B) The $ATP$ yield is calculated based on the oxidation of these substrates in the Krebs cycle and the subsequent Electron Transport System $(ETS)$.$

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$1-s, 2-q, 3-p, 4-r$

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(B) The $ATP$ yield is calculated based on the oxidation of these substrates in the Krebs cycle and the subsequent Electron Transport System $(ETS)$.$1$. Succinic acid enters the Krebs cycle and produces $1$ $FADH_2$ ($1.5$ $ATP$) and $1$ $GTP$ ($1$ $ATP$) plus $1$ $NADH$ ($2.5$ $ATP$) during its conversion to oxaloacetate,totaling $5$ $ATP$. Thus,$1-s$.$2$. Citric acid oxidation in the Krebs cycle produces $3$ $NADH$ ($7.5$ $ATP$),$1$ $FADH_2$ ($1.5$ $ATP$),and $1$ $GTP$ ($1$ $ATP$),totaling $10$ $ATP$. However,considering the full oxidation of the acetyl group derived from citrate,the value is $15$ $ATP$. Thus,$2-q$.$3$. Pyruvate oxidation yields $1$ $NADH$ (link reaction) + $3$ $NADH$ + $1$ $FADH_2$ + $1$ $GTP$ in the Krebs cycle,totaling $12$ $ATP$. Thus,$3-p$.$4$. $\alpha$-ketoglutaric acid oxidation yields $2$ $NADH$ + $1$ $FADH_2$ + $1$ $GTP$,totaling $9$ $ATP$. Thus,$4-r$.Therefore,the correct match is $1-s, 2-q, 3-p, 4-r$.

Match the following:
$1$. Succinic acid $p$. $12$ $ATP$
$2$. Citric acid $q$. $15$ $ATP$
$3$. Pyruvate $r$. $9$ $ATP$
$4$. $\alpha$-ketoglutaric acid $s$. $5$ $ATP$

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$1$. Succinic acid	$p$. $12$ $ATP$
$2$. Citric acid	$q$. $15$ $ATP$
$3$. Pyruvate	$r$. $9$ $ATP$
$4$. $\alpha$-ketoglutaric acid	$s$. $5$ $ATP$

Match the following:$1$. Succinic acid$p$. $12$ $ATP$$2$. Citric acid$q$. $15$ $ATP$$3$. Pyruvate$r$. $9$ $ATP$$4$. $\alpha$-ketoglutaric acid$s$. $5$ $ATP$